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The function \( g(x) = -x^3 + 21 \) has a domain of all real numbers, a range of \( (-\infty, 21] \), a y-intercept at (0, 21), and an x-intercept at \( \left(\sqrt[3]{21}, 0\right) \). It has a maximum point at (0, 21).
Solución
To analyze the function \( g(x) = -x^3 + 21 \), we can explore various features such as its domain, range, intercepts, and critical points. Let's go through these step by step.
### Step 1: Domain
The domain of a polynomial function is all real numbers. Therefore, the domain of \( g(x) \) is:
\[
\text{Domain: } (-\infty, \infty)
\]
### Step 2: Range
Since \( g(x) \) is a cubic function with a negative leading coefficient, it will decrease without bound as \( x \) approaches positive infinity and increase without bound as \( x \) approaches negative infinity. The maximum value occurs at the vertex. To find the maximum value, we can find the critical points by taking the derivative and setting it to zero.
### Step 3: Finding Critical Points
Let's calculate the derivative \( g'(x) \):
\[
g'(x) = -3x^2
\]
Setting the derivative equal to zero to find critical points:
\[
-3x^2 = 0
\]
This gives:
\[
x = 0
\]
### Step 4: Evaluating \( g(x) \) at Critical Points
Now, we evaluate \( g(x) \) at \( x = 0 \):
\[
g(0) = -0^3 + 21 = 21
\]
### Step 5: Range Conclusion
Since the function decreases to negative infinity as \( x \) moves away from 0 in both directions, the range of \( g(x) \) is:
\[
\text{Range: } (-\infty, 21]
\]
### Step 6: Intercepts
- **Y-intercept**: This occurs when \( x = 0 \):
\[
g(0) = 21 \quad \text{(Y-intercept: (0, 21))}
\]
- **X-intercepts**: Set \( g(x) = 0 \):
\[
-x^3 + 21 = 0 \implies x^3 = 21 \implies x = \sqrt[3]{21}
\]
Thus, the x-intercept is:
\[
\text{X-intercept: } \left(\sqrt[3]{21}, 0\right)
\]
### Summary of Features
- **Domain**: \( (-\infty, \infty) \)
- **Range**: \( (-\infty, 21] \)
- **Y-intercept**: \( (0, 21) \)
- **X-intercept**: \( \left(\sqrt[3]{21}, 0\right) \)
- **Critical Point**: Maximum at \( (0, 21) \)
If you need further analysis or specific calculations, please let me know!
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