4. Peter travels at an average speed of \( 98 \mathrm{~km} / \mathrm{h} \) for 3 hours. He then travels at al average speed of \( 105 \mathrm{~km} / \mathrm{h} \) for 2 hours. 4.1 What was the total distance he travelled? 4.2 Caiculate his average speed over the whole distance. 5. A car travels for 2 hours and covers a distance of 240 km . How long will it take to cover a distance of 540 km at the same constant average speed?

Peter's adventure on the open road can be calculated with ease! For the distance he traveled, we can use the formula \( \text{Distance} = \text{Speed} \times \text{Time} \). He covers \( 98 \, \text{km/h} \) for \( 3 \, \text{hours} \) and \( 105 \, \text{km/h} \) for \( 2 \, \text{hours} \). That gives us \( 294 \, \text{km} \) + \( 210 \, \text{km} \), totaling \( 504 \, \text{km} \). Now, let's figure out his average speed! The total time he spent traveling is \( 3 + 2 = 5 \) hours. The average speed is calculated with \( \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \). So, we have \( \frac{504 \, \text{km}}{5 \, \text{hours}} = 100.8 \, \text{km/h} \). Talk about a speedy trip! For the car's journey, we start with the known facts. If it traveled \( 240 \, \text{km} \) in \( 2 \, \text{hours} \), its average speed was \( \frac{240 \, \text{km}}{2 \, \text{hours}} = 120 \, \text{km/h} \). To find out how long it takes to cover \( 540 \, \text{km} \) at that same speed, we can rearrange our distance formula: \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \). Plugging in the values, \( \frac{540 \, \text{km}}{120 \, \text{km/h}} = 4.5 \, \text{hours} \). So, buckle up for 4 hours and 30 minutes of journey time!