A special deck of cards has 5 red tards, and 4 purple cards. The red cards are numbered 1, 2, 3, 4, and 5 . . The purple cards are numbered \( 1,2,3 \), and 4 . The cards are well shuffled and you randomly draw one card. \( \mathrm{R}= \) card drawn is red \( \mathrm{E}= \) card drawn is even-numbered a. How many elements are there in the sample space? b. \( \mathrm{P}(\mathrm{E})=\square \) Round your answer to two decimal places. Hint: Sample Space and Probability Video on Probability
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Bonus Knowledge
In this deck of cards, you have a total of 9 cards: 5 red (1, 2, 3, 4, 5) and 4 purple (1, 2, 3, 4). Therefore, the sample space (S) consists of these 9 cards, making a total of 9 elements. So, we can say |S| = 9. Now, for event E (drawing an even-numbered card), we identify the even cards: 2, 4 (red), and 2, 4 (purple), giving us a total of 4 even-numbered cards. To find P(E), we use the formula P(E) = Number of favorable outcomes / Total outcomes = 4/9. Approximating this fraction yields P(E) ≈ 0.44 when rounded to two decimal places. Isn't it fascinating how probability helps us understand the likelihood of different outcomes in a fun card game? You can think of it like preparing for a game night where knowing your chances can strategize your wins! Now, if you're interested in deepening your understanding of probability, consider exploring the concepts of independent and dependent events. These ideas are vital in realizing how one event's occurrence might affect another's, and they can enhance your games or everyday decision-making in incredible ways!
