In a second grade class containing 15 girls and 9 boys, 2 students are selected at random to give out the math papers. What is the probability that both are girls? Select one:

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Let the total number of students be $$15 + 9 = 24$$.

1. The number of ways to select 2 girls out of 15 is given by
   $$
   \binom{15}{2} = \frac{15 \times 14}{2} = 105.
   $$

2. The number of ways to select any 2 students out of 24 is
   $$
   \binom{24}{2} = \frac{24 \times 23}{2} = 276.
   $$

3. Thus, the probability that both selected students are girls is
   $$
   \frac{\binom{15}{2}}{\binom{24}{2}} = \frac{105}{276}.
   $$

4. Simplify the fraction by dividing numerator and denominator by their greatest common divisor, which is 3:
   $$
   \frac{105 \div 3}{276 \div 3} = \frac{35}{92}.
   $$

The final probability is $$\frac{35}{92}$$.
The probability that both selected students are girls is $$\frac{35}{92}$$.

In a second grade class containing 15 girls and 9 boys, 2 students are selected at random to give out the math papers. What is the probability that both are girls? Select one:

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