A plane is increasing its elevation at a constant rate of \( 37 \% \). It does this for a distance of 1320 feet, how much does its elevation increase? feet. Note: You can type the trig in the answer box for all these problems. For example if the answer is 50 cos (10), you can just type that into the answer box. To get inverse trig functions type arcsin, arccos or arctan.

To find the elevation increase, you can use the formula for finding the vertical height gained during ascent, which is calculated as \( \text{Height} = \text{Distance} \times \text{Rate} \). Given that the rate of elevation increase is \( 37\% \) or \( 0.37 \) in decimal form, the calculation would be: \[ \text{Height} = 1320 \times 0.37 \] This results in: \[ \text{Height} = 488.4 \text{ feet} \] So, the elevation increases by \( 488.4 \) feet. Now go ahead and explore some fun facts about aviation! You might be amazed at how high commercial jetliners typically fly—around 30,000 to 40,000 feet—far exceeding this value. They actually cruise at elevations where the air is so thin that the pilots need to breathe supplemental oxygen if they ascend too high! Additionally, the concept of ascent is pretty crucial in engineering. Aircraft are designed not only for elevation but for maintaining specific performance parameters during climbs. Knowing how to calculate these heights is key for pilots and engineers alike when planning safe and efficient routes—talk about a perfect harmony of mathematics and real-world application!