2 If \( 2 x^{2}-5 x+\mathrm{a}=(2 x-3)(x-1) \), then \( \mathrm{a}=\cdots \cdots \ldots \ldots \ldots \ldots \) (a) 2

To find the value of \( a \), we first need to expand the right side of the equation \( (2x - 3)(x - 1) \). Expanding it gives: \[ (2x - 3)(x - 1) = 2x^2 - 2x - 3x + 3 = 2x^2 - 5x + 3. \] Now we have: \[ 2x^2 - 5x + a = 2x^2 - 5x + 3. \] For the equations to be equal, the constants must also be equal, which means: \[ a = 3. \] So, \( a = 3 \).