\begin{tabular}{l} QUESTION \( 11 \cdot 1 \) POINT \\ Solve \( \log [9(x-8)]=\log [3(2 x)] \) \\ Do not include " \( x= \) " in your answer. \\ Provide your answer below: \\ \hline\end{tabular}

To solve \( \log [9(x-8)] = \log [3(2x)] \), we can use the property that if \( \log A = \log B \), then \( A = B \). This gives us the equation: \[ 9(x - 8) = 3(2x) \] Now, let's simplify it: \[ 9x - 72 = 6x \] Subtract \( 6x \) from both sides: \[ 3x - 72 = 0 \] Now, add 72 to both sides: \[ 3x = 72 \] Finally, divide by 3: \[ x = 24 \] Thus, the answer is: 24