he function \( f \) is defined below. \[ f(x)=\frac{x-4}{x^{2}+3 x-40} \] ind all values of \( x \) that are NOT in the domain of \( f \). f there is more than one value, separate them with commas. \( x=\square \)

1. The function is defined as \[ f(x)=\frac{x-4}{x^{2}+3 x-40} \] 2. To find values that are not in the domain, we must determine when the denominator is zero. Set the denominator equal to zero: \[ x^{2}+3 x-40=0. \] 3. Factor the quadratic expression. Look for two numbers that multiply to \(-40\) and add to \(3\). These numbers are \(8\) and \(-5\). Thus, the factorization is: \[ (x+8)(x-5)=0. \] 4. Set each factor equal to zero and solve: \[ x+8=0 \quad \Rightarrow \quad x=-8, \] \[ x-5=0 \quad \Rightarrow \quad x=5. \] 5. Therefore, the values that are not in the domain of \( f \) are \( x=-8 \) and \( x=5 \). \( x=-8,\,5 \)