50.5(3-2x) when $$ x=2 $$ $$ \begin{array}{l}5(3-2(2)) \ 5(2)\end{array} $$

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UpStudy AI · Accepted Answer

Calculate the value by following steps:
- step0: Calculate:
  $$50.5\left(3-2\times 2\right)$$
- step1: Multiply the numbers:
  $$50.5\left(3-4\right)$$
- step2: Subtract the numbers:
  $$50.5\left(-1\right)$$
- step3: Multiply the numbers:
  $$-50.5$$
Let's solve the expression $$ 50.5(3-2x) $$ when $$ x=2 $$ step by step.

1. **Substituting $$ x=2 $$**:
   $$
   50.5(3-2(2))
   $$

2. **Calculating inside the parentheses**:
   $$
   2(2) = 4
   $$
   So, we have:
   $$
   50.5(3-4)
   $$

3. **Continuing with the calculation**:
   $$
   3-4 = -1
   $$
   Now, the expression becomes:
   $$
   50.5(-1)
   $$

4. **Final calculation**:
   $$
   50.5 \times -1 = -50.5
   $$

Thus, the final result is:
$$
-50.5
$$

This matches the calculations you provided, confirming that the expression evaluates to $$-50.5$$.
When $$ x = 2 $$, the expression $$ 50.5(3 - 2x) $$ equals $$-50.5$$.

50.5(3-2x) when \( x=2 \) \( \begin{array}{l}5(3-2(2)) \\ 5(2)\end{array} \)

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