1.1) \( -2 x+3=11 \) 1.2) \( 2-3(x+3)=2 x+3 \) 1.3) \( 5(x+2)=5 x+10 \) 1.4) \( 5(y-2)-2(y+1)=3(y-5) \)

1.1) Solve \( -2x + 3 = 11 \): - Subtract \(3\) from both sides: \[ -2x = 11 - 3 = 8 \] - Divide by \(-2\): \[ x = \frac{8}{-2} = -4 \] --- 1.2) Solve \( 2 - 3(x+3) = 2x + 3 \): - Expand the left-hand side: \[ 2 - 3x - 9 = 2x + 3 \] - Combine like terms: \[ -3x - 7 = 2x + 3 \] - Add \(3x\) to both sides: \[ -7 = 5x + 3 \] - Subtract \(3\) from both sides: \[ -10 = 5x \] - Divide by \(5\): \[ x = -2 \] --- 1.3) Solve \( 5(x+2) = 5x + 10 \): - Expand the left-hand side: \[ 5x + 10 = 5x + 10 \] Since both sides are identical, the equation is true for every \(x\): \[ x \in \mathbb{R} \] --- 1.4) Solve \( 5(y-2) - 2(y+1) = 3(y-5) \): - Expand both sides: \[ 5y - 10 - 2y - 2 = 3y - 15 \] - Combine like terms on the left: \[ 3y - 12 = 3y - 15 \] - Subtract \(3y\) from both sides: \[ -12 = -15 \] Since \(-12 \neq -15\), the equation has no solution.