Pregunta
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1. A basketball court has the dimensions shown. A border with a width of \( x \) feet is built surrounding the basketball court. What the perimeter of the basketball court and border? Write the expression in simplest form.

Ask by Harrington Kirk. in the United States
Feb 25,2025

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The perimeter of the basketball court with the border is \( 268 + 8x \) feet.

Solución

We start with the fact that the border is built all around the basketball court. This means that on each side the border adds x feet. So if the court’s original length is L and its width is W, then with the border the new length and width become   Length with border = L + 2x   Width with border = W + 2x The perimeter of a rectangle is given by twice the sum of its length and width. Therefore, the new perimeter P is   P = 2[(L + 2x) + (W + 2x)]     = 2[L + W + 4x]     = 2(L + W) + 8x If the diagram shows, for example, that the basketball court measures 84 feet by 50 feet (a common size), then L = 84 and W = 50. Plugging these values in gives   P = 2(84 + 50) + 8x     = 2(134) + 8x     = 268 + 8x Thus, in simplest form, the expression for the perimeter of the basketball court with its border is   268 + 8x feet.

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The Deep Dive

The perimeter of the basketball court can be calculated using the formula for the perimeter of a rectangle: \( P = 2 \times (\text{length} + \text{width}) \). If we assume the dimensions of the basketball court are \( l \) and \( w \), the perimeter would be \( 2(l + w) \). However, with a border of width \( x \), the overall dimensions become \( (l + 2x) \) and \( (w + 2x) \). Therefore, the perimeter of the court plus the border is \( 2((l + 2x) + (w + 2x)) = 2(l + w + 4x) \). Now you have a dynamic expression that changes with the border width, making it quite the mathematical adventure! To avoid common mistakes, make sure to account for the border width correctly. Often, it's easy to forget to add \( 2x \) to both the length and width, which would lead to an incorrect perimeter calculation. Always double-check your dimensions!

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