Pregunta
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Jen is a biologist studying endangered and at-nisk species in Mongolia. When she first started studying the snow leopard population, she estimated that there were 1,000 snow leopards in Mongolia. After one year, Jen estimated that the population had decreased to 990 . She expects the snow leopard population to continue decreasing each year. Write an exponential equation in the form \( y=a(b)^{\prime} \) that can model the estimated snow leopard population in Mongolis, \( y \), in \( \times \) years. Use whole numbers, decimals, or simplified fractions for the values of a and b. \[ y=\square \text {. } \] To the nearest whole number, how many snow leopards can Jen expect there to be in Mongolia in 5 years? snow leopards

Ask by Morrison Harrington. in the United States
Mar 11,2025

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The exponential equation is \( y = 1000(0.99)^x \). In 5 years, Jen can expect there to be approximately 951 snow leopards.

Solución

\[ \textbf{Step 1: Set Up the Exponential Model} \] The general form of the exponential model is \[ y = a(b)^x, \] where: - \( a \) is the initial population, - \( b \) is the decay factor, - \( x \) is the number of years. Since Jen estimated there were 1,000 snow leopards initially, we have: \[ a = 1000. \] \[ \textbf{Step 2: Determine the Decay Factor \( b \)} \] After 1 year, the population was estimated at 990. Plug \( x = 1 \) and \( y = 990 \) into the model: \[ 990 = 1000(b)^1. \] Solve for \( b \): \[ b = \frac{990}{1000} = 0.99. \] \[ \textbf{Step 3: Write the Exponential Equation} \] The exponential model is: \[ y = 1000(0.99)^x. \] \[ \textbf{Step 4: Estimate the Population in 5 Years} \] To find the population after 5 years, set \( x = 5 \) in the equation: \[ y = 1000(0.99)^5. \] Calculate \( (0.99)^5 \): \[ (0.99)^5 \approx 0.95099. \] Thus, \[ y \approx 1000 \times 0.95099 \approx 950.99. \] \[ \textbf{Step 5: Round the Answer} \] Rounding to the nearest whole number: \[ y \approx 951. \] \[ \textbf{Final Answers:} \] 1. The exponential equation is: \[ y = 1000(0.99)^x. \] 2. In 5 years, Jen can expect there to be approximately 951 snow leopards.

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To create the exponential equation, we start with the initial population as our starting value \( a \). Jen estimated the initial population of snow leopards to be 1,000. The decrease from 1,000 to 990 means there’s a decrease of \( \frac{990}{1000} = 0.99 \) after one year. Thus, we can express the equation as follows: \[ y = 1000(0.99)^{t} \] where \( t \) is the number of years. Now, to calculate how many snow leopards there will be in 5 years, we substitute \( t = 5 \) into the equation: \[ y = 1000(0.99)^5 \] \[ y \approx 1000 \times 0.95099 \] \[ y \approx 951 \] Therefore, to the nearest whole number, Jen can expect there to be approximately **951 snow leopards** in Mongolia in 5 years.

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\( \varphi=\arctan \left(\frac{y}{x}\right) \) Penulisan system koordinat polar adalah \( r<\varphi \) Sebaliknya, untuk mengkonversi dari system koordinat polar menuju system koordinat cartesian seperti pada persamaan berikut: \[ \begin{array}{l} x=r \cdot \cos (\varphi) \\ y=r \cdot \sin (\varphi) \end{array} \] Untuk operasi penjumlahan dan pengurangan harus diubah ke system koordinat cartesian. Sedangkan untuk operasi perkalian dan pembagian dapat dilakukan dengan sangat mudah. Misal \( A=4 \angle 60^{\circ} \) dan \( B=2 \angle 20^{\circ} \) Perkalian: \( A \cdot B=\left(4 \angle 60^{\circ}\right) \cdot\left(2 \angle 20^{\circ}\right) \) Dalam proses perkalian, jari-jari (r) dikalikan, sedangkan sudut \( (\varphi) \) dijumlahkan. \( A \cdot B=(4.2) \angle\left(60^{\circ}+20^{\circ}\right) \) A. \( B=8 \angle 80^{\circ} \) Pembagian: \[ \frac{A}{B}=\frac{4 \angle 60^{\circ}}{2 \angle 20^{\circ}} \] Dalam proses pembagian, jari-jari ( \( r \) ) dibagi seperti biasa, sedangkan sudut \( (\varphi) \) pembilangdikurangi sudut penyebut. \[ \begin{array}{l} \frac{A}{B}=\frac{4}{2} \angle\left(60^{\circ}-20^{\circ}\right) \\ \frac{A}{B}=2 \angle 40^{\circ} \end{array} \] Tugas 1. (harus diseertai dengan cara) 1. Tentukan hasil dari \( \sqrt{-13.69} \) Diketahui \( A=1.5+0.5 i \) dan \( B=1+2.5 i \), maka tentukan: 2. \( A+B \) 3. \( A-B \) 4. \( A * B \) 5. \( \frac{A}{B} \) 6. \( \frac{A^{2}-A B}{B} \) 7. Bentuk polar A 8. Bentuk polar \( B \) 9. \( A * B \) dengan cara polar 10. \( \frac{A}{B} \) dengan cara polar 11. Bentuk cartesian dari jawaban no. 9 dan bandinglan hasilnya dengan jawaban no. 4 12. Bentuk cartesian dari jawaban no. 10 dan bandingkan hasilnya dengan jawaban no.5. Materi selanjutnya -> Euler dan Teorema de Moivre.

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