Find the remainder. \( \begin{array}{l}\frac{x^{3}+23}{x+3} \\ \text { The remainder is: } \\ 0+4 \\ -4 \\ -29 \\ 29\end{array} \)

To find the remainder of \( \frac{x^{3}+23}{x+3} \), we can use the Remainder Theorem. This theorem states that for a polynomial \( f(x) \), the remainder of the division by \( x-c \) is \( f(c) \). In this case, let \( f(x) = x^3 + 23 \) and \( c = -3 \). Now we evaluate \( f(-3) \): \[ f(-3) = (-3)^3 + 23 = -27 + 23 = -4. \] So, the remainder when \( x^3 + 23 \) is divided by \( x + 3 \) is \( -4 \). Thus, the remainder is: \(-4\).