Evaluate the piecewise function at the given values of the indopendent variable. \( f(x)=\left\{\begin{array}{ll}5 x+4 & \text { fix<0 } \\ 3 x+7 & \text { If } x \geq 0\end{array}\right. \) (a) \( f(-1) \) (b) \( f(0) \) (c) \( f(3) \) (a) \( f(-1)=\square \) (b) \( f(0)=\square \) (c) \( f(3)=\square \)

To evaluate the piecewise function for the given values of the independent variable, we will follow the definitions provided in the function. (a) Since \(-1 < 0\), we will use the first part of the piecewise function: \( f(-1) = 5(-1) + 4 = -5 + 4 = -1 \). So, \( f(-1) = -1 \). (b) For \( f(0) \), since \( 0 \geq 0\), we will use the second part of the function: \( f(0) = 3(0) + 7 = 0 + 7 = 7 \). Thus, \( f(0) = 7 \). (c) Finally, for \( f(3) \), because \( 3 \geq 0\), we again use the second part of the function: \( f(3) = 3(3) + 7 = 9 + 7 = 16 \). Therefore, \( f(3) = 16 \). Now, summarizing our findings: (a) \( f(-1) = -1 \) (b) \( f(0) = 7 \) (c) \( f(3) = 16 \)