Solve the equation for \( x \) \[ \frac{x}{3}-\frac{3}{4}=\frac{2 x+5}{12} \] \( x=\square \)

To solve the equation \[ \frac{x}{3}-\frac{3}{4}=\frac{2 x+5}{12}, \] start by finding a common denominator for all the fractions involved. The common denominator for 3, 4, and 12 is 12. Rewrite each term with this common denominator: \[ \frac{x}{3} = \frac{4x}{12}, \quad -\frac{3}{4} = -\frac{9}{12}, \quad \text{and} \quad \frac{2x+5}{12} = \frac{2x+5}{12}. \] Now substitute these back into the equation: \[ \frac{4x}{12} - \frac{9}{12} = \frac{2x + 5}{12}. \] Since the denominators are all the same, you can eliminate them: \[ 4x - 9 = 2x + 5. \] Next, get all the \(x\) terms on one side and the constants on the other side. Subtract \(2x\) from both sides: \[ 4x - 2x - 9 = 5. \] This simplifies to: \[ 2x - 9 = 5. \] Now, add 9 to both sides: \[ 2x = 14. \] Finally, divide by 2 to solve for \(x\): \[ x = 7. \] So the solution is \[ x = 7. \]