Refer to functions \( s \) and \( t \). Find the indicated function and write the domain in interval notation. \[ s(x)=\frac{x-1}{x^{2}-9} \] Part: \( 0 / 2 \) Part 1 of 2

Find the function \( s(x)=\frac{x-1}{x^{2}-9} \). Simplify the expression by following steps: - step0: Solution: \(\frac{x-1}{x^{2}-9}\) The function \( s(x) \) is given by \( s(x) = \frac{x-1}{x^{2}-9} \). To find the domain of the function, we need to determine the values of \( x \) for which the function is defined. The function is defined as long as the denominator \( x^{2}-9 \) is not equal to zero. To find the values of \( x \) that make the denominator zero, we set \( x^{2}-9 = 0 \) and solve for \( x \): \[ x^{2}-9 = 0 \] \[ x^{2} = 9 \] \[ x = \pm 3 \] Therefore, the function is not defined at \( x = 3 \) and \( x = -3 \). The domain of the function \( s(x) \) is all real numbers except \( x = 3 \) and \( x = -3 \), which can be written in interval notation as: \[ (-\infty, -3) \cup (-3, 3) \cup (3, \infty) \]