\begin{tabular}{l|l} (D) 60 seeds & \\ 4. Josh bought \( 1 \frac{1}{3} \) pounds of ground & 7. H \\ beef and \( 2 \frac{1}{3} \) pounds of ground \\ turkey. How much meat did Josh & \\ buy in all? \\ (A) 1 pound & \\ (B) \( 1 \frac{2}{3} \) pounds & 8. \\ (C) \( 3 \frac{1}{3} \) pounds & \end{tabular}

To find out how much meat Josh bought in total, we need to add the weights of the ground beef and ground turkey. First, we convert the mixed numbers into improper fractions for easier addition. For the ground beef: \[ 1 \frac{1}{3} = \frac{4}{3} \text{ pounds} \] For the ground turkey: \[ 2 \frac{1}{3} = \frac{7}{3} \text{ pounds} \] Now, we can add these two fractions: \[ \frac{4}{3} + \frac{7}{3} = \frac{4 + 7}{3} = \frac{11}{3} \text{ pounds} \] Converting \(\frac{11}{3}\) back to a mixed number gives us: \[ 3 \frac{2}{3} \text{ pounds} \] So, Josh bought a total of \( 3 \frac{2}{3} \) pounds of meat. Now, check the choices you provided; it seems like there might have been a typo, as none of the options match this total. Additional tip: Remember to check your answers, especially in a multiple-choice question, as calculations can lead to unexpected results! Failing to convert mixed numbers into improper fractions before adding can lead to mistakes in addition. A common trap is assuming you can add the whole numbers and fractions separately without adjusting for like denominators. Always ensure you’re working with fractions that have the same denominators to avoid confusion!