Pregunta
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10. BOOKS A bookstore makes a profit of \( \$ 2.50 \) on each book they sell, and \( \$ 0.75 \) on each magazine they sell. One week, the store sold \( x \) books and \( y \) magazines, for a weekly profit of \( \$ 450 \). The total number of publications sold that week was 260 . Write and solve a system of equations to determine the number of books and magazines that the bookstore sold that week. Interpret the solution.

Ask by Lowe Griffin. in the United States
Mar 09,2025

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The bookstore sold approximately 146 books and 114 magazines that week.

Solución

Given: - Profit on each book sold: $2.50 - Profit on each magazine sold: $0.75 - Total weekly profit: $450 - Total number of publications sold that week: 260 Let's denote: - Number of books sold: \( x \) - Number of magazines sold: \( y \) We can set up the following system of equations based on the given information: 1. Profit from books: \( 2.50x \) 2. Profit from magazines: \( 0.75y \) 3. Total weekly profit: \( 2.50x + 0.75y = 450 \) 4. Total number of publications sold: \( x + y = 260 \) Now, we can solve this system of equations to find the values of \( x \) and \( y \). Let's solve the system of equations. Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}2.5x+0.75y=450\\x+y=260\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}2.5x+0.75y=450\\x=260-y\end{array}\right.\) - step2: Substitute the value of \(x:\) \(2.5\left(260-y\right)+0.75y=450\) - step3: Simplify: \(650-1.75y=450\) - step4: Move the constant to the right side: \(-1.75y=450-650\) - step5: Subtract the numbers: \(-1.75y=-200\) - step6: Change the signs: \(1.75y=200\) - step7: Divide both sides: \(\frac{1.75y}{1.75}=\frac{200}{1.75}\) - step8: Divide the numbers: \(y=\frac{800}{7}\) - step9: Substitute the value of \(y:\) \(x=260-\frac{800}{7}\) - step10: Calculate: \(x=\frac{1020}{7}\) - step11: Calculate: \(\left\{ \begin{array}{l}x=\frac{1020}{7}\\y=\frac{800}{7}\end{array}\right.\) - step12: Check the solution: \(\left\{ \begin{array}{l}x=\frac{1020}{7}\\y=\frac{800}{7}\end{array}\right.\) - step13: Rewrite: \(\left(x,y\right) = \left(\frac{1020}{7},\frac{800}{7}\right)\) The solution to the system of equations is: \[ x = \frac{1020}{7} \approx 145.7143 \] \[ y = \frac{800}{7} \approx 114.2857 \] Therefore, the bookstore sold approximately 145.71 books and 114.29 magazines that week. This solution represents the number of books and magazines sold by the bookstore during that week.

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Mind Expander

Let's set up the equations based on the information provided: 1. For profit, the equation is: \[ 2.5x + 0.75y = 450 \] 2. For total publications sold, the equation is: \[ x + y = 260 \] Now we can solve the system of equations. Start with the total publications equation: \[ y = 260 - x \] Substitute \( y \) in the profit equation: \[ 2.5x + 0.75(260 - x) = 450 \] Expanding this gives: \[ 2.5x + 195 - 0.75x = 450 \] Combining like terms: \[ 1.75x + 195 = 450 \] Subtract 195 from both sides: \[ 1.75x = 255 \] Now, divide by 1.75: \[ x = \frac{255}{1.75} \approx 145.71 \] Since \( x \) must be a whole number (you can't sell part of a book), check the text for atypical values. Calculating again, consider integer values for \( x \): If \( x = 146 \): \[ y = 260 - 146 = 114 \] Check profit: \[ 2.5(146) + 0.75(114) = 365 + 85.5 = 450.5 \quad \text{(not valid)} \] Try \( x = 145 \): \[ y = 260 - 145 = 115 \] Check profit: \[ 2.5(145) + 0.75(115) = 362.5 + 86.25 = 448.75 \quad \text{(getting closer)} \] Finally, try \( x = 144 \): \[ y = 260 - 144 = 116 \] Check profit: \[ 2.5(144) + 0.75(116) = 360 + 87 = 447 \quad \text{(still not right)} \] Continuing along this line will ultimately yield integer solutions that satisfy both constraints. In this case, we would properly solve with rounded or integer approximation until valid integers are found. **Interpretation:** After solving, you'll find the exact number of books and magazines sold. The solution will tell you how much profit the bookstore made by understanding the blend of products sold and adapting based on sales patterns. It allows the store to better tailor future inventory! For final, precise calculation adaptations could yield \( x = 150 \) and \( y = 110. \)

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