If $$ \ln (4 x+3)=1 $$, then $$ x=\square $$ Question Help: Qideo

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Solve the equation $$ \ln(4x+3)=1 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$\ln{\left(4x+3\right)}=1$$
- step1: Find the domain:
  $$\ln{\left(4x+3\right)}=1,x>-\frac{3}{4}$$
- step2: Convert the logarithm into exponential form:
  $$4x+3=e^{1}$$
- step3: Evaluate the power:
  $$4x+3=e$$
- step4: Move the constant to the right side:
  $$4x=e-3$$
- step5: Divide both sides:
  $$\frac{4x}{4}=\frac{e-3}{4}$$
- step6: Divide the numbers:
  $$x=\frac{e-3}{4}$$
- step7: Check if the solution is in the defined range:
  $$x=\frac{e-3}{4},x>-\frac{3}{4}$$
- step8: Find the intersection:
  $$x=\frac{e-3}{4}$$
The solution to the equation $$ \ln(4x+3)=1 $$ is $$ x = \frac{e-3}{4} $$.
$$ x = \frac{e - 3}{4} $$

If \( \ln (4 x+3)=1 \), then \( x=\square \) Question Help: Qideo

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