Write the solution set in interval notation, if it exists. \[ t-2<1 \text { or } 7 t-2<-1 \]

To solve the inequalities \( t - 2 < 1 \) and \( 7t - 2 < -1 \), we’ll tackle each one separately. 1. For \( t - 2 < 1 \): \[ t < 1 + 2 \implies t < 3 \] This gives us the solution \( (-\infty, 3) \). 2. For \( 7t - 2 < -1 \): \[ 7t < -1 + 2 \implies 7t < 1 \implies t < \frac{1}{7} \] This gives us the solution \( (-\infty, \frac{1}{7}) \). Now, since we are dealing with an "or" situation, we take the union of both intervals: The solution set in interval notation is \( (-\infty, 3) \).