Given: \( \cos 44^{\circ}=a \) Use a sketch to calculate the following. (Do not use a calculator.) (a) \( \sin 46^{\circ} \) (b) \( \tan \left(-764^{\circ}\right) \) (c) \( \sin 89^{\circ} \) (d) \( \cos 88^{\circ} \) (e) \( \sin 22^{\circ} \)
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To solve the given problems, we will use trigonometric identities and properties based on the relationship between angles. (a) We know that \( \sin(90^\circ - \theta) = \cos(\theta) \). Therefore: \[ \sin 46^{\circ} = \sin(90^{\circ} - 44^{\circ}) = \cos 44^{\circ} = a \] (b) To find \( \tan(-764^\circ) \), we can simplify it by finding an equivalent angle in the range \( [0^\circ, 360^\circ) \): \[ -764^\circ + 720^\circ = -44^\circ \] Now, use the property that \( \tan(-\theta) = -\tan(\theta): \) \[ \tan(-764^\circ) = \tan(-44^\circ) = -\tan(44^\circ) \] (c) For \( \sin 89^\circ \), we can use the identity \( \sin(90^\circ - \theta) = \cos(\theta): \) \[ \sin 89^{\circ} = \sin(90^{\circ} - 1^{\circ}) = \cos 1^\circ \] (d) Using the co-function identity \( \cos(90^\circ - \theta) = \sin(\theta): \) \[ \cos 88^{\circ} = \cos(90^{\circ} - 2^{\circ}) = \sin 2^{\circ} \] (e) The sine and cosine relationship comes into play here as well: Using \( \sin(90^\circ - \theta) = \cos(\theta) \), we can find \( \sin 22^\circ \) through its complement: \[ \sin 22^{\circ} = \cos(90^{\circ} - 22^{\circ}) = \cos 68^{\circ} \] In summary, the results are: (a) \( \sin 46^{\circ} = a \) (b) \( \tan(-764^{\circ}) = -\tan(44^{\circ}) \) (c) \( \sin 89^{\circ} = \cos(1^{\circ}) \) (d) \( \cos 88^{\circ} = \sin 2^{\circ} \) (e) \( \sin 22^{\circ} = \cos 68^{\circ} \)
