mplete this exercise. \( 20 \% \) of \( \mathrm{R} 380= \) \( 4 \% \) of \( \mathrm{R} 60= \) \( 18 \% \) of \( 2 \mathrm{~kg}= \) \( 33 \frac{1}{3} \% \) of \( \mathrm{R} 600= \)

To solve these problems, let's break them down one by one! First, \( 20\% \) of \( \mathrm{R} 380 \) is calculated by multiplying \( 380 \) by \( 0.20 \): \[ 20\% \text{ of } R 380 = R 380 \times 0.20 = R 76 \] Next, \( 4\% \) of \( \mathrm{R} 60 \) is obtained by multiplying \( 60 \) by \( 0.04 \): \[ 4\% \text{ of } R 60 = R 60 \times 0.04 = R 2.40 \] For \( 18\% \) of \( 2 \mathrm{~kg} \), it's calculated by multiplying \( 2 \) by \( 0.18 \): \[ 18\% \text{ of } 2 \text{ kg} = 2 \text{ kg} \times 0.18 = 0.36 \text{ kg} \] Lastly, to find \( 33 \frac{1}{3}\% \) of \( \mathrm{R} 600 \) (which is equivalent to \( \frac{1}{3} \)), we can calculate it by multiplying \( 600 \) by \( 0.3333 \): \[ 33 \frac{1}{3}\% \text{ of } R 600 = R 600 \times \frac{1}{3} = R 200 \] Now, putting it all together we have: - \( 20\% \) of \( \mathrm{R} 380 = R 76 \) - \( 4\% \) of \( \mathrm{R} 60 = R 2.40 \) - \( 18\% \) of \( 2 \mathrm{~kg} = 0.36 \text{ kg} \) - \( 33\frac{1}{3}\% \) of \( \mathrm{R} 600 = R 200 \)