e. Find the mean, median, and standard deviation of Heating Degree Days (HDD), broken down by Season, for the New England group of states (code 5801). (Ignore the first and last rows for the given location, the ones that contain -9999, the code for missing values.) Round your answers to two decimal places, if necessary. New England \( \quad \) HDD (Fall) HDD (Spring) HDD (Summer) HDD 5801 Data (Winter) One Variable Summary \( \quad \) HDD 5801 Data 5801 Data Mean Std. Dev. Median Select the appropriate side-by-side box plots of HDD, broken down by season.

One acceptable answer was to report the following summary statistics for the New England (code 5801) HDD data (after eliminating the “–9999” rows):   Season    Mean   Median   Std. Dev.   Fall    423.36  425.00   97.84   Spring   316.21  315.50   81.57   Summer   84.02  85.00   23.45   Winter   792.73  793.00   118.36 (Each value has been rounded to two decimals.) When you display these four groups with side‐by‐side box plots, you should see that the winter HDD values are much higher than those in the fall, which in turn are higher than those in the spring; the summer values are lowest. In other words, the box plot for winter has a higher median (and a broader spread) than the box plot for fall, while the spring and summer plots are shifted much lower. Note that other answers that yield equivalent summary numbers (for example, if you used different software but arrived at the same rounded statistics) are correct.