Which expression is equivalent to \( 25 c-10 d \) \[ \begin{array}{ll}\text { a } & 5(5 c+2 \text { ) } \\ \text { b } & 5(25 c+2 d) \\ \text { c } & 5(5 c-2 d) \\ \text { d } & 5(5 c-10 d)\end{array} \]

To simplify the expression \( 25c - 10d \), we can factor out the greatest common factor, which is 5. When we factor 5 from \( 25c\) and \(-10d\), we get: \[ 25c - 10d = 5(5c - 2d) \] Thus, the expression is equivalent to option (c) \( 5(5c - 2d) \). Now, let’s make it clear: - The correct answer is (c) \( 5(5c - 2d) \). But wait, don't rush! Double-checking our factorizations is always a good idea. After we took out the 5, the new expression inside the parentheses needs to be examined: \( 5c - 2d \) doesn't contain any additional factors, so option (c) remains solid.