(a). Kisiwaa puts \( \frac{1}{4} \) of her salary in savings and uses \( \frac{1}{2} \) of the remaining money to pay back her sister. If the amount left is GHC \( 2,400.00 \), how much did she have as salary? (b). A dance academy charges GHC 20.00 to use the facility and GHC 25 per hour of instruction. (i) Write an equation that gives the total cost to learn at the dance academy as a function of hours of instruction. (ii) Find the total cost of 2 hours of dance instruction. Find the perimeter and area of the shape below. (c).
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Beyond the Answer
Kisiwaa’s salary puzzle is a classic example of problem-solving with fractions! To find her salary, let’s denote her salary as \( S \). After saving \( \frac{1}{4}S \), she has \( \frac{3}{4}S \) left. If she pays back her sister \( \frac{1}{2} \) of this remaining amount, she uses \( \frac{1}{2} \times \frac{3}{4}S = \frac{3}{8}S \). After these transactions, she’s left with GHC \( 2,400.00 \), leading to the equation \( \frac{3}{8}S = 2400 \). Solving this gives her salary as GHC \( 6,400.00 \). At the dance academy, the total cost can be calculated easily! If you use \( H \) to represent hours of instruction, the total cost \( C \) can be expressed as: \[ C = 20 + 25H \]. For 2 hours of dance instruction, plug in \( H \): \[ C = 20 + 25(2) = 20 + 50 = GHC 70.00 \]. So, the total cost for 2 hours is GHC 70.00 — time to dance!
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