a) Chandrakala has a square garden of length 18 m .
(i) Find its perimeter.
(ii) Find the length of wire required to fence it with three rounds.
(iii) If the rate of cost of fencing is Rs 25 per metre, find the total cost o
fencing.
b) 540 m of wire is required to fence a square shaped of fish pond with three rounds
(i) What is the length of wire required for one round?
(ii) What is the perimeter of the pond?
(iii) Find the length of the pond.

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UpStudy AI · Accepted Answer

**a) Chandrakala's Square Garden**

Let the side of the square be $$ s = 18 $$ m.

**(i) Perimeter of the Garden**

A square's perimeter is given by:
$$
P = 4 \times s
$$
Substitute $$ s = 18 $$ m:
$$
P = 4 \times 18 = 72 \text{ m}
$$

**(ii) Length of Wire Required for Three Rounds**

For three rounds, the total wire length is:
$$
\text{Total wire} = 3 \times P = 3 \times 72 = 216 \text{ m}
$$

**(iii) Total Cost of Fencing**

If the cost per meter is Rs 25, then the total cost is:
$$
\text{Cost} = 216 \times 25 = 5400 \text{ Rupees}
$$

---

**b) Square Shaped Fish Pond**

The total wire used for three rounds is $$ 540 $$ m.

**(i) Length of Wire for One Round**

Let the wire required for one round be $$ L $$. Since three rounds use $$ 540 $$ m:
$$
3L = 540 \quad \Rightarrow \quad L = \frac{540}{3} = 180 \text{ m}
$$

**(ii) Perimeter of the Pond**

Since the pond is square shaped, the perimeter is equal to $$ L $$ for one round:
$$
P = 180 \text{ m}
$$

**(iii) Length of One Side of the Pond**

Let the length of one side be $$ s $$. The perimeter of a square is:
$$
P = 4 \times s
$$
Substitute $$ P = 180 $$ m:
$$
4s = 180 \quad \Rightarrow \quad s = \frac{180}{4} = 45 \text{ m}
$$
**a) Chandrakala's Square Garden** - **Perimeter:** 72 meters - **Wire for Three Rounds:** 216 meters - **Total Fencing Cost:** Rs 5,400 **b) Square Shaped Fish Pond** - **Wire per Round:** 180 meters - **Perimeter:** 180 meters - **Length of One Side:** 45 meters

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