h) \( 4 x^{2}+9 x-9 \)

To tackle the quadratic equation \( 4 x^{2}+9 x-9 \), one can begin by applying the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a, b, \) and \( c \) are coefficients from the standard form \( ax^2 + bx + c = 0 \). For this equation, your \( a = 4 \), \( b = 9 \), and \( c = -9 \). Plugging those into the formula gives you the roots of the equation! Now, when trying to factor a quadratic equation like this, be cautious! A common misstep is assuming all quadratics can be easily factored into simple binomials. In this case, it might not break down neatly, so don’t hesitate to revert to the quadratic formula as your reliable trusty sidekick. It's there for you when factoring fails!