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Finance Morksheet- Profit and LOSS Continued 3D Yaseen bought a house for R2950000. He spent R125000 for renovation of the house when he bought it. Each year he spends R11000 on maintenance of the house. After 11 years, he sells the house for R3736000. How much profit did he make? a. R551000 \( \begin{array}{ll}\text { c. R529000 } & \text { b. R562000 }\end{array} \) Michael buys 140 guitars from a wholesale market paying R224 for each item, and then he makes a profit by selling each one at \( \frac{5}{4} \) of the price he bought them at. How much money did he have after selling them all? \( \begin{array}{ll}\text { a. R37285 } & \text { b. R39040 } \\ \text { c. R39200 } & \text { d. R39627 }\end{array} \)

Ask by Hobbs Brooks. in South Africa
Feb 19,2025

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Yaseen made a profit of R539,000. Michael earned a total of R39,200 after selling all the guitars.

Solución

Let's solve the problems step by step. ### Problem 1: Yaseen's House Profit Calculation 1. **Initial Cost of the House**: - Purchase Price = R2950000 - Renovation Cost = R125000 - Total Initial Cost = Purchase Price + Renovation Cost \[ \text{Total Initial Cost} = 2950000 + 125000 = 3075000 \] 2. **Maintenance Costs Over 11 Years**: - Annual Maintenance Cost = R11000 - Total Maintenance Cost over 11 years = Annual Maintenance Cost × Number of Years \[ \text{Total Maintenance Cost} = 11000 \times 11 = 121000 \] 3. **Total Cost After 11 Years**: - Total Cost = Total Initial Cost + Total Maintenance Cost \[ \text{Total Cost} = 3075000 + 121000 = 3197000 \] 4. **Selling Price of the House**: - Selling Price = R3736000 5. **Profit Calculation**: - Profit = Selling Price - Total Cost \[ \text{Profit} = 3736000 - 3197000 = 539000 \] Now, let's check the options provided: - a. R551000 - b. R562000 - c. R529000 The calculated profit of R539000 does not match any of the options provided. Let's double-check the calculations. ### Problem 2: Michael's Guitar Profit Calculation 1. **Cost of Guitars**: - Number of Guitars = 140 - Cost per Guitar = R224 - Total Cost = Number of Guitars × Cost per Guitar \[ \text{Total Cost} = 140 \times 224 = 31360 \] 2. **Selling Price per Guitar**: - Selling Price = \( \frac{5}{4} \) of the Cost Price \[ \text{Selling Price per Guitar} = \frac{5}{4} \times 224 = 280 \] 3. **Total Selling Price**: - Total Selling Price = Number of Guitars × Selling Price per Guitar \[ \text{Total Selling Price} = 140 \times 280 = 39200 \] Now, let's check the options provided: - a. R37285 - b. R39040 - c. R39200 - d. R39627 The calculated total selling price of R39200 matches option c. ### Summary of Results 1. Yaseen's Profit: R539000 (not matching any options) 2. Michael's Total Money After Selling Guitars: R39200 (option c) If you need further assistance or clarification, feel free to ask!

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Mind Expander

Let’s break down Yaseen’s situation first! After buying the house for R2,950,000 and spending R125,000 on renovations, he has a total cost of R3,075,000. With annual maintenance adding R11,000 over 11 years (which totals R121,000), his total expenditure reaches R3,196,000. Selling the house for R3,736,000 gives him a profit of R540,000 (R3,736,000 - R3,196,000)! So, the closest answer, rounding up, would be **b. R562,000**. Now, let’s strum over Michael's guitars! He buys 140 guitars at R224 each, which sums up to a total cost of R31,360 (140 x R224). By selling each guitar at \( \frac{5}{4} \) of the purchase price, he sells them for R280 (R224 x \( \frac{5}{4} \)). For 140 guitars, the total revenue comes to R39,200 (140 x R280). Adding that, Michael ends up with a profit of R7,840 (R39,200 - R31,360)! So, he has **c. R39,200** after selling them all! 🎸💰

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