There are 10 people at a meeting and there are 4 different door prizes to give out. How many ways can we select 4 people to receive the door prizes?
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Beyond the Answer
When it comes to selecting people for door prizes, we can use the concept of combinations since the order in which we choose the winners does not matter. The formula for combinations is given by \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of people and \( r \) is the number of prize winners we want. In this case, we have \( n = 10 \) and \( r = 4 \). Plugging these numbers into the formula gives us: \[ C(10, 4) = \frac{10!}{4!(10-4)!} = \frac{10!}{4! \times 6!} = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1} = 210 \] Therefore, there are 210 different ways to select 4 individuals out of 10 to receive the door prizes! Imagine all the excitement as the names are drawn; 210 different combinations mean a myriad of ways the grand prize winners could change the vibe of the meeting!
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