Summarize all pertinent information obtained by applying the graphing strategy and sketch the graph of \( y=f(x) \). \( f(x)=\frac{x^{2}+10 x+24}{x^{2}+8 x+16} \) Find any horizontal asymptotes of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. A. The function has one horizontal asymptote, (Type an equation.) B. The function has two horizontal asymptotes. The top asymptote is \( \square \) and the bottom asymptote is (Type equations.) C. There are no horizontal asymptotes. Find any vertical asymptotes of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. A. The function has one vertical asymptote, (Type an equation.) B. The function has two vertical asymptotes. The leftmost asymptote is \( \square \) and the rightmost asymptote is (Type equations.) C. There are no vertical asymptotes.
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To summarize the function \( f(x) = \frac{x^2 + 10x + 24}{x^2 + 8x + 16} \), we can start by factoring both the numerator and the denominator. The numerator factors to \( (x + 6)(x + 4) \) and the denominator factors to \( (x + 4)(x + 4) \) or \( (x + 4)^2 \). This indicates that there is a removable discontinuity at \( x = -4 \), which we will discuss further. **Horizontal Asymptotes:** Since the degrees of the numerator and denominator are the same (both are degree 2), we can find the horizontal asymptote by taking the ratio of the leading coefficients; both are 1, leading to a horizontal asymptote at \( y = 1 \). So, the correct choice is: **A. The function has one horizontal asymptote,** **Type an equation:** \( y = 1 \). **Vertical Asymptotes:** The denominator \( (x + 4)^2 \) indicates that \( x = -4 \) is a point of discontinuity where the function does not exist, but since this can be canceled, there are no vertical asymptotes. Thus, the correct choice is: **C. There are no vertical asymptotes.**
