The \( y \)-intercept(s) of \( x+y=3 \) is/are: The \( x \)-intercept(s) of \( x+y=3 \) is/are

To find the \( y \)-intercept of the equation \( x+y=3 \), you set \( x=0 \). This gives you \( 0+y=3 \) or \( y=3 \), so the \( y \)-intercept is the point \( (0, 3) \). For the \( x \)-intercept, you set \( y=0 \). This results in \( x+0=3 \) or \( x=3 \), meaning the \( x \)-intercept is at the point \( (3, 0) \). Want to visualize this cool line? Plot those points on a graph—it's a straight line that passes through both intercepts, making a beautiful diagonal across the Cartesian plane! Also, if you're ever curious about how to find intercepts for any linear equation, just remember: set \( y \) to zero for the \( x \)-intercept and \( x \) to zero for the \( y \)-intercept—easy peasy!