a) \( \left(a^{4} \cdot b^{3}\right)^{3} \cdot\left(a^{2} \cdot b\right)^{2}= \) b) \( \frac{\left(a^{3} \cdot b^{-2}\right)^{-2}}{\left(a^{-4} b^{3}\right)^{3}}= \)
Solución de inteligencia artificial de Upstudy
Responder
Solución
Respondido por UpStudy AI y revisado por un tutor profesional


The Deep Dive
For part a), let’s simplify step by step! First, apply the power of a power rule: \( (x^m)^n = x^{m \cdot n} \). This gives you \( a^{12} \cdot b^{9} \) from the first part and \( a^{4} \cdot b^{2} \) from the second. Now combine them using the product rule: \( a^{12+4} \cdot b^{9+2} = a^{16} \cdot b^{11} \). Voilà, the answer is \( a^{16} \cdot b^{11} \)! For part b), remember that a negative exponent means you take the reciprocal. Rewrite the expression to find \( a^{-3} \cdot b^{4} \) on top and \( a^{-12} \cdot b^{9} \) on the bottom. Now simplify: when you divide, you subtract the exponents of the same base. The result is \( a^{9} \cdot b^{-5} \), which can also be presented as \( \frac{a^{9}}{b^{5}} \). And there you have it, \( \frac{a^{9}}{b^{5}} \)!
