Question Find the solution of the system of equations. \[ -3 x-7 y=18 \] \[ 9 x+2 y=3 \] \( \begin{array}{l}\text { Answer Attempt tout of a } \\ (\square), \square) \text { Submit Answer }\end{array} \)

To solve the system of equations given, we can use the substitution or elimination method. Let's start by rearranging the first equation: 1. From \( -3x - 7y = 18 \), we can express \( y \): \( 7y = -3x - 18 \) \( y = -\frac{3}{7}x - \frac{18}{7} \) 2. Now, substitute this expression for \( y \) into the second equation \( 9x + 2y = 3 \): \( 9x + 2\left(-\frac{3}{7}x - \frac{18}{7}\right) = 3 \) Simplifying, we have: \( 9x - \frac{6}{7}x - \frac{36}{7} = 3 \) Clearing the fraction by multiplying through by 7 gives: \( 63x - 6x - 36 = 21 \) Combine like terms: \( 57x = 57 \) Thus, \( x = 1 \). 3. Substitute \( x = 1 \) back into the equation for \( y \): \( y = -\frac{3}{7}(1) - \frac{18}{7} \) \( y = -\frac{3}{7} - \frac{18}{7} = -\frac{21}{7} = -3 \). So, the solution to the system of equations is: \( (1, -3) \). \( \text{Submit Answer: } (1, -3) \)