Pregunta
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Find the \( x \) and \( y \) coordinates of all inflection points. \( f(x)=4 x^{\frac{5}{3}}+5 \) What is/are the inflection point(s)? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The inflection point(s) is/are (Type an ordered pair. Use a comma to soparate answers as needed.) B. There are no inflection points.

Ask by Kirk Mathis. in the United States
Mar 11,2025

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The inflection point is at \((0, 5)\).

Solución

1. Write the function: \[ f(x)=4x^{\frac{5}{3}}+5 \] 2. Find the first derivative \( f'(x) \): \[ f'(x)=4\cdot\frac{5}{3}x^{\frac{5}{3}-1}=\frac{20}{3}x^{\frac{2}{3}} \] 3. Compute the second derivative \( f''(x) \): \[ f''(x)=\frac{20}{3}\cdot\frac{2}{3}x^{\frac{2}{3}-1}=\frac{40}{9}x^{-\frac{1}{3}}=\frac{40}{9x^{\frac{1}{3}}} \] 4. Determine where \( f''(x) \) is zero or undefined. The expression \( f''(x)=\frac{40}{9x^{\frac{1}{3}}} \) is undefined at \( x=0 \). 5. Check the sign of \( f''(x) \) around \( x=0 \): - For \( x>0 \), \( x^{\frac{1}{3}}>0 \) so \( f''(x)>0 \). - For \( x<0 \), \( x^{\frac{1}{3}}<0 \) (since the cube root of a negative number is negative) so \( f''(x)<0 \). The sign of \( f''(x) \) changes at \( x=0 \), indicating an inflection point. 6. Find the \( y \)-coordinate of the inflection point by evaluating \( f(0) \): \[ f(0)=4\cdot0^{\frac{5}{3}}+5=5 \] 7. Therefore, the inflection point is: \[ (0,5) \] Answer choice A is correct with the inflection point \((0,5)\).

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Extra Insights

To find the inflection points of the function \( f(x) = 4x^{\frac{5}{3}} + 5 \), we first need to find the second derivative. 1. Find the first derivative \( f'(x) \): \[ f'(x) = \frac{d}{dx}(4x^{\frac{5}{3}}) = \frac{20}{3}x^{\frac{2}{3}} \] 2. Find the second derivative \( f''(x) \): \[ f''(x) = \frac{d}{dx}\left(\frac{20}{3}x^{\frac{2}{3}}\right) = \frac{20}{9}x^{-\frac{1}{3}} \] 3. Set the second derivative equal to zero to identify potential inflection points: \[ \frac{20}{9}x^{-\frac{1}{3}} = 0 \] Since the term \( x^{-\frac{1}{3}} \) can never equal zero, we check where it's undefined. The expression is undefined at \( x = 0 \). Now check the sign changes around \( x = 0 \): - For \( x < 0 \): \( f''(x) > 0 \) - For \( x > 0 \): \( f''(x) < 0 \) This indicates that there is a change in concavity around \( x = 0 \). So, the inflection point is at \( (0, f(0)) \): \[ f(0) = 4(0)^{\frac{5}{3}} + 5 = 5 \] Thus, the inflection point is \( (0, 5) \). A. The inflection point(s) is/are (0, 5)

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