In a circle, a \( 180^{\circ} \) sector has area \( 98 \pi \mathrm{in}^{2} \). What is the radius of the circle? The radius of the circle is \( \square \mathrm{in} \). (Simplify your answer.)
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The area \( A \) of a sector of a circle is given by the formula: \[ A = \frac{\theta}{360} \times \pi r^2 \] where \( \theta \) is the angle in degrees, and \( r \) is the radius. For a \( 180^{\circ} \) sector, this simplifies to: \[ A = \frac{180}{360} \times \pi r^2 = \frac{1}{2} \pi r^2 \] We know the area is \( 98 \pi \), so we set up the equation: \[ \frac{1}{2} \pi r^2 = 98 \pi \] Dividing both sides by \( \pi \): \[ \frac{1}{2} r^2 = 98 \] Multiplying both sides by 2: \[ r^2 = 196 \] Taking the square root: \[ r = \sqrt{196} = 14 \] Thus, the radius of the circle is \( 14 \, \mathrm{in} \).
