a) \( \frac{32 a b c}{64 a c} \times \frac{8 h c}{4 b^{2}} \)
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Extra Insights
First, we simplify the expression step by step. Start with the first fraction: \[ \frac{32 a b c}{64 a c} = \frac{32 b}{64} = \frac{1}{2} b \quad \text{(since } a \text{ and } c \text{ cancel out)} \] Next, simplify the second fraction: \[ \frac{8 h c}{4 b^{2}} = \frac{2 h c}{b^{2}} \quad \text{(dividing both the numerator and the denominator by 4)} \] Now, multiply these simplified fractions: \[ \frac{1}{2} b \times \frac{2 h c}{b^{2}} = \frac{1}{2} \times \frac{2 h c b}{b^{2}} = \frac{h c}{b} \] Thus, the final simplified expression is: \[ \frac{h c}{b} \]
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