Consider the sequence \[ a_{n}=\frac{n \cdot \cos (n)}{5 n+10} \] Describe the behavior of the sequence. Is the sequence monotone? Monotone decreasing for all n Is the sequence bounded? Select Determine whether the sequence converges or diverges. If it converges, find the value it converges to. If it diverges, enter DIV.
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The Deep Dive
To analyze the behavior of the sequence \( a_n = \frac{n \cdot \cos(n)}{5n + 10} \), we first observe that as \( n \) becomes large, the \( \cos(n) \) term oscillates between -1 and 1. Therefore, the sequence will oscillate, but the overall fraction will approach a definite value since \( \frac{n}{5n + 10} \) behaves like \( \frac{1}{5} \). 1. **Behavior and Boundedness**: The sequence is indeed bounded. Since \( \cos(n) \) oscillates between -1 and 1, we can evaluate the expression for extreme cases, yielding: \[ -\frac{n}{5n + 10} \leq a_n \leq \frac{n}{5n + 10}. \] For large \( n \), both bounds approach \( -\frac{1}{5} \) and \( \frac{1}{5} \). Thus, the sequence is bounded between \( -\frac{1}{5} \) and \( \frac{1}{5} \). 2. **Monotonicity**: The sequence is not monotone. The oscillatory nature of \( \cos(n) \) ensures that \( a_n \) will not consistently increase or decrease, given that \( \cos(n) \) takes on various values repetitively, creating fluctuations in \( a_n \). 3. **Convergence**: To find out if the sequence converges, we analyze the limit as \( n \) approaches infinity: \[ \lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{n \cdot \cos(n)}{5n + 10} = \lim_{n \to \infty} \frac{\cos(n)}{5 + \frac{10}{n}}. \] Since \( \cos(n) \) oscillates between -1 and 1, the limit does not settle on a specific value. Therefore, the sequence diverges. In conclusion, the sequence does not converge to a single point and oscillates within the range defined, while being bounded. **Final answer: DIV**
