Find an equation for the line with the given properties. Express the equation in slope-intercept fo Slope \( =-4 \); containing the point \( (6,-5) \) What is the equation of the line? (Typs your answer in slope-intercept form.)

To find the equation of the line with a slope of -4 that passes through the point (6, -5), we can use the point-slope form of the equation of a line, which is \( y - y_1 = m(x - x_1) \). Here, \( m \) is the slope and \( (x_1, y_1) \) is the point on the line. Plugging in the slope and the point, we have: \( y - (-5) = -4(x - 6) \) Now simplify: \( y + 5 = -4x + 24 \) Subtract 5 from both sides to isolate \( y \): \( y = -4x + 19 \) So, the equation of the line in slope-intercept form is \( y = -4x + 19 \). This line is like those swanky retro shirts back in the day—cool slope and a great connection to the point!