Find the \( x \)-intercept(s). and \( y \)-intercept(s). of the graph of the following. \[ 64 x^{2}+4 y^{2}=1 \] If there is more than one answer, separate them with commas. Click on "None" if applicable. \( x \)-intercept(s): \( y \)-intercept(s):

To find the \( x \)-intercept(s), set \( y = 0 \) in the equation \( 64 x^2 + 4 y^2 = 1 \). This gives us: \[ 64 x^2 + 4(0)^2 = 1 \implies 64 x^2 = 1 \implies x^2 = \frac{1}{64} \implies x = \pm \frac{1}{8}. \] So, the \( x \)-intercepts are \( x = \frac{1}{8}, -\frac{1}{8} \). Next, for the \( y \)-intercept(s), set \( x = 0 \): \[ 64(0)^2 + 4 y^2 = 1 \implies 4 y^2 = 1 \implies y^2 = \frac{1}{4} \implies y = \pm \frac{1}{2}. \] Thus, the \( y \)-intercepts are \( y = \frac{1}{2}, -\frac{1}{2} \). Final answers: \( x \)-intercept(s): \( \frac{1}{8}, -\frac{1}{8} \) \( y \)-intercept(s): \( \frac{1}{2}, -\frac{1}{2} \)