Use the Quotient Rule to evaluate and simplify \( \frac{d}{d x}\left(\frac{x-4}{5 x-2}\right) \). \( \frac{d}{d x}\left(\frac{x-4}{5 x-2}\right)=\square \)
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To evaluate the derivative using the Quotient Rule, recall that if you have a function in the form \( \frac{u}{v} \), the derivative is given by \( \frac{u'v - uv'}{v^2} \). Here, let \( u = x - 4 \) and \( v = 5x - 2 \). First, compute \( u' \) and \( v' \): - \( u' = 1 \) - \( v' = 5 \) Now, apply the Quotient Rule: \[ \frac{d}{dx}\left(\frac{x-4}{5x-2}\right) = \frac{(1)(5x-2) - (x-4)(5)}{(5x-2)^2} \] Simplifying the numerator: \[ = \frac{(5x - 2) - (5x - 20)}{(5x - 2)^2} = \frac{5x - 2 - 5x + 20}{(5x - 2)^2} = \frac{18}{(5x - 2)^2} \] Thus, the simplified derivative is: \[ \frac{d}{dx}\left(\frac{x-4}{5x-2}\right) = \frac{18}{(5x-2)^2} \]
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