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2. \( \frac{-2(a-1)(a+2)(a-2)}{2(1-a)} \)

Ask by Smith Ortega. in South Africa
Feb 20,2025

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The simplified form is \( a^2 - 4 \).

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To simplify the expression \( \frac{-2(a-1)(a+2)(a-2)}{2(1-a)} \), notice that the \(2\) in the numerator and the denominator can be canceled out: \[ \frac{-2(a-1)(a+2)(a-2)}{2(1-a)} = \frac{-(a-1)(a+2)(a-2)}{1-a} \] Next, we can rewrite \(1-a\) as \(-(a-1)\): \[ \frac{-(a-1)(a+2)(a-2)}{-(a-1)} = (a+2)(a-2) \] Finally, we can simplify further into the difference of squares: \[ (a+2)(a-2) = a^2 - 4 \] Thus, the simplified form is: \[ a^2 - 4 \]

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