\( \quad=2 x-4 x^{2} y+7 x y-14 y^{2} \) \( =2 x^{6}+3 x^{3} y-14 y^{2} \) SQUARING A BINOMIAL (REVISION OF GRADE 9)

To square a binomial, we use the formula: \[ (a + b)^2 = a^2 + 2ab + b^2 \] In this case, it seems you have two expressions, but they are not in the form of a binomial. Let's clarify the expressions you provided: 1. \( 2x - 4x^2y + 7xy - 14y^2 \) 2. \( 2x^6 + 3x^3y - 14y^2 \) If you want to square a binomial, we need to identify a binomial first. Let's assume you want to square the first expression as a binomial. ### Step 1: Identify the Binomial Let's consider the first expression \( 2x - 4x^2y + 7xy - 14y^2 \). We can group terms to form a binomial. However, it seems more complex than a simple binomial. ### Step 2: Simplify the Expression Let's simplify the first expression: \[ 2x + (7xy - 4x^2y) - 14y^2 \] This doesn't form a clear binomial. ### Step 3: Squaring a Binomial Example If we take a simple binomial, for example, \( (a + b) \), squaring it would look like this: Let’s say \( a = 2x \) and \( b = -4y \): \[ (2x - 4y)^2 = (2x)^2 + 2(2x)(-4y) + (-4y)^2 \] Calculating each term: 1. \( (2x)^2 = 4x^2 \) 2. \( 2(2x)(-4y) = -16xy \) 3. \( (-4y)^2 = 16y^2 \) Putting it all together: \[ (2x - 4y)^2 = 4x^2 - 16xy + 16y^2 \] ### Conclusion If you have a specific binomial you want to square, please provide it, and I can help you with that. If you want to simplify or manipulate the expressions you provided, please clarify your request!