10) \( \begin{array}{c}-4 x+9 y=9 \\ x-3 y=-6\end{array} \)
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Beyond the Answer
To solve the system of equations given by \( -4x + 9y = 9 \) and \( x - 3y = -6 \), let's first isolate \( x \) in the second equation. Rearranging gives us \( x = 3y - 6 \). Now, substitute this expression for \( x \) into the first equation: \[ -4(3y - 6) + 9y = 9. \] Distributing the \(-4\) yields: \[ -12y + 24 + 9y = 9. \] Now combine like terms: \[ -3y + 24 = 9. \] Subtract 24 from both sides: \[ -3y = -15. \] Dividing by \(-3\) results in: \[ y = 5. \] Now, substitute \( y = 5 \) back into the equation for \( x \): \[ x = 3(5) - 6 = 15 - 6 = 9. \] Thus, the solution to the system of equations is \( x = 9 \) and \( y = 5 \). In summary, the final solution is \( (x, y) = (9, 5) \).
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