Pregunta
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Current Skill SHC My friend Mimstoon bought some yoys for \( \$ 2 \) each and some pisquets for \( \$ 6 \) each. The total cost was about \( \$ 36 \). Altogether, he bought 12 items. Here are equations showing the relationship between yoys \( (\mathrm{x}) \) and pisquets (y): \[ \begin{array}{l} 8 x+y=12 \\ 2 x+6 y=36 \end{array} \] How many yoys and pisquets did he buy? \( \not \subset 0 \) yoys, 3 pisquets 13 yoys, 3 pisquets 9 yoys, 3 pisquets 3 yoys, 9 pisquets

Ask by Bernard Page. in the United States
Feb 24,2025

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Mimstoon bought 9 yoys and 3 pisquets.

Solución

Let x be the number of yoys and y be the number of pisquets. We have two conditions: 1. The total number of items is 12:   x + y = 12 2. The total cost is $36, with yoys costing $2 each and pisquets costing $6 each:   2x + 6y = 36 Step 1. Solve the first equation for x:   x = 12 − y Step 2. Substitute x into the cost equation:   2(12 − y) + 6y = 36   24 − 2y + 6y = 36   24 + 4y = 36 Step 3. Solve for y:   4y = 36 − 24   4y = 12   y = 3 Step 4. Substitute y back into the first equation:   x + 3 = 12   x = 12 − 3   x = 9 Thus, Mimstoon bought 9 yoys and 3 pisquets. Among the given options, the correct choice is:   9 yoys, 3 pisquets.

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Mind Expander

To solve this system of equations, let's take a closer look at the information provided. The first equation \(8x + y = 12\) indicates the total number of items and can be rewritten to find \(y\) in terms of \(x\): \(y = 12 - 8x\). The second equation, \(2x + 6y = 36\), can be simplified to find a relationship between \(x\) and \(y\) as well. Now, substituting \(y\) in terms of \(x\) into the second equation, we have \(2x + 6(12 - 8x) = 36\). This simplifies to \(2x + 72 - 48x = 36\), leading us to \( -46x = -36\). Solving for \(x\), we get \(x = 9/23\), which isn't a valid integer solution given that \(x\) must be a whole number. This suggests we need to directly plug in the answer choices provided. Evaluating the alternatives: 1. For \(0\) yoys and \(3\) pisquets: \(2(0) + 6(3) = 18\). 2. For \(13\) yoys and \(3\) pisquets: \(2(13) + 6(3) = 38\). 3. For \(9\) yoys and \(3\) pisquets: \(2(9) + 6(3) = 30\). 4. For \(3\) yoys and \(9\) pisquets: \(2(3) + 6(9) = 60\). To find the combo that yields a total cost of \(36\) with \(12\) items, all of the solutions have shown incorrect pairing for quantities and costs. Upon quick recalculation and reframing by substituting choices, we identify that \(3\) yoys and \(9\) pisquets actually hit the required quantity and total but our per piece costs showed up mismatched. Therefore, the math here is slightly askew. Review further might prompt pairings that certify into combination of ratios than whole plug-value checks. So, the final answers to fit the equations correctly are \(6\) yoys and \(6\) pisquets since they would yield the required total in constraints. This mix of logic and substitution guides the thought process alongside validations to confirm counts and expenditure harnessed by the answer checks run for balance in approach.

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