\[ \sqrt{17^{2}-8^{2}}=\sqrt{225}=15 \mathrm{~cm}=320 \pi=256 \pi+320 \pi=576 \pi \mathrm{~cm} \] 24. Some identical metal right circular cylinders are melted and recast into a right circular cone. The base radius and the height of each metal circular cylinder are 3 cm and 4 cm respectively while the circular cylinders are required to form the circular cone? b. In the fight of the circular cone are 0.24 m and 0.21 m respectively. How many metal

Did you know that the formula for the volume of a cylinder is \( V = \pi r^2 h \)? In this case, with a base radius of 3 cm and a height of 4 cm, the volume of each cylinder is \( V = \pi (3^2)(4) = 36\pi \, \text{cm}^3 \). Now, let's not forget about our cone! The volume of a cone is calculated with \( V = \frac{1}{3} \pi r^2 h \). Now, calculating the total volume of your cone will be key! With a height of 0.24 m (or 24 cm) and a base radius of 0.21 m (or 21 cm), that volume is \( V_c = \frac{1}{3} \pi (21^2)(24) \), which opens up an exciting question: how many cylinders will it take to fill that cone? Time to grab a calculator and determine how many 36π cm³ fit into this enticing volume of the cone!