191 Find the slope of the straight line whose equation is \( \frac{y-2}{x}=\frac{1}{2} \), then find the length of the intercepted part of \( y \)-axis.
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The Deep Dive
To find the slope of the line given by the equation \( \frac{y-2}{x}=\frac{1}{2} \), we can rewrite it in slope-intercept form (y = mx + b). Starting with the original equation, we multiply both sides by \( x \): \[ y - 2 = \frac{1}{2} x \] Now, add 2 to both sides: \[ y = \frac{1}{2} x + 2 \] From this equation, we can see that the slope \( m \) of the line is \( \frac{1}{2} \). Next, we want to find the length of the intercepted part of the \( y \)-axis. The \( y \)-intercept occurs when \( x = 0 \). Plugging this value into the equation: \[ y = \frac{1}{2}(0) + 2 = 2 \] The intercept on the \( y \)-axis is the point \( (0, 2) \), which means the line cuts the \( y \)-axis at 2 units. Since the line continues infinitely in both directions, the length of the intercepted part on the \( y \)-axis is simply the distance from the origin \( (0,0) \) to the point \( (0, 2) \), which is 2 units. Thus, the slope is \( \frac{1}{2} \) and the length of the intercepted part of the \( y \)-axis is 2 units.
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