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Math \( 126 \quad \) Written Homework 11 (extra credit) If you choose tó not do these problems, please do not turn in the assignment. 1. (extra credit 10 pts.) Consider the function of two variables given by \( f(x, y)=\frac{1}{2}(x+y+|x-y|) \) Experiment with \( f \) on scratch paper for various real-number inputs in place o \( x \) and \( y \). Show two of the calculations below and briefly explain what this function does.

Ask by Bowman Graham. in the United States
Mar 13,2025

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The function \( f(x, y) = \frac{1}{2}(x + y + |x - y|) \) returns the larger of the two numbers \( x \) and \( y \). For example, if \( x = 3 \) and \( y = 1 \), \( f(3,1) = 3 \), and if \( x = 2 \) and \( y = 5 \), \( f(2,5) = 5 \).

Solución

1. The given function is \[ f(x,y)=\frac{1}{2}(x+y+|x-y|). \] 2. To understand the behavior of \( f \), consider two cases based on the relationship between \( x \) and \( y \). - **Case 1: \( x \geq y \)** When \( x \geq y \), we have \[ |x-y| = x-y. \] Substituting into the function: \[ f(x,y)=\frac{1}{2}(x+y+(x-y))=\frac{1}{2}(2x)=x. \] - **Case 2: \( x < y \)** When \( x < y \), we have \[ |x-y| = y-x. \] Substituting into the function: \[ f(x,y)=\frac{1}{2}(x+y+(y-x))=\frac{1}{2}(2y)=y. \] 3. From these calculations, we see that: \[ f(x, y) = \begin{cases} x & \text{if } x \geq y, \\ y & \text{if } x < y. \end{cases} \] In other words, \( f(x,y) \) returns the maximum of \( x \) and \( y \). 4. **Sample Calculations:** - **Example 1:** Let \( x=3 \) and \( y=1 \). Since \( 3 \geq 1 \), \[ f(3,1)=3. \] - **Example 2:** Let \( x=2 \) and \( y=5 \). Since \( 2 < 5 \), \[ f(2,5)=5. \] Thus, the function \( f(x, y)=\frac{1}{2}(x+y+|x-y|) \) calculates the maximum of the two inputs \( x \) and \( y \).

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Extra Insights

When you plug in various values for \( x \) and \( y \), you can truly appreciate the role of the absolute value in determining the output of the function. For example, if \( x = 2 \) and \( y = 3 \), the calculation goes as follows: \( f(2, 3) = \frac{1}{2}(2 + 3 + |2 - 3|) = \frac{1}{2}(5 + 1) = \frac{6}{2} = 3 \). This indicates that the function computes an average of the values while considering the relationship between them, specifically their difference. Another interesting pair could be \( x = 5 \) and \( y = 1\): \( f(5, 1) = \frac{1}{2}(5 + 1 + |5 - 1|) = \frac{1}{2}(6 + 4) = \frac{10}{2} = 5 \). Here, it reflects that \( f(x, y) \) effectively captures the larger of the two numbers as the function averages the sum and the absolute difference, ensuring a balance between their values.

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