Solve the system by elimination. \( \left\{\begin{array}{l}3 x+4 y=4 \\ -x-3 y=-8\end{array}\right. \) One solution: ONo solution O Infinite number of solutions

Solve the system of equations \( 3x+4y=4;-x-3y=-8 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}3x+4y=4\\-x-3y=-8\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}3x+4y=4\\x=8-3y\end{array}\right.\) - step2: Substitute the value of \(x:\) \(3\left(8-3y\right)+4y=4\) - step3: Simplify: \(24-5y=4\) - step4: Move the constant to the right side: \(-5y=4-24\) - step5: Subtract the numbers: \(-5y=-20\) - step6: Change the signs: \(5y=20\) - step7: Divide both sides: \(\frac{5y}{5}=\frac{20}{5}\) - step8: Divide the numbers: \(y=4\) - step9: Substitute the value of \(y:\) \(x=8-3\times 4\) - step10: Calculate: \(x=-4\) - step11: Calculate: \(\left\{ \begin{array}{l}x=-4\\y=4\end{array}\right.\) - step12: Check the solution: \(\left\{ \begin{array}{l}x=-4\\y=4\end{array}\right.\) - step13: Rewrite: \(\left(x,y\right) = \left(-4,4\right)\) The system of equations has a unique solution, which is \( x = -4 \) and \( y = 4 \). Therefore, the solution is \( (-4, 4) \).