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The function \( y = 4 \cdot 2^{x-2} + 1 \) is an exponential function that has been transformed as follows:
- **Horizontal Shift**: Shifted 2 units to the right.
- **Vertical Scaling**: Stretched vertically by a factor of 4.
- **Vertical Shift**: Moved upward by 1 unit.
Key points include:
- **Domain**: All real numbers.
- **Range**: \( y > 1 \).
- **Y-intercept**: (0, 2).
- **Point on Graph**: (2, 5).
Overall, it's an exponentially increasing curve with the specified transformations.
Solución
The function
y = 4 · 2^(x – 2) + 1
is an exponential function obtained by transforming the basic exponential f(x) = 2^x. Here’s a breakdown of its features and transformations:
1. Base Function:
• The original exponential function is f(x) = 2^x.
2. Horizontal Shift:
• The exponent (x – 2) means the graph is shifted to the right by 2 units.
3. Vertical Scaling:
• Multiplying 2^(x – 2) by 4 stretches the graph vertically by a factor of 4.
4. Vertical Shift:
• Finally, adding 1 moves the entire graph upward by 1 unit.
5. Domain and Range:
• Domain: All real numbers (–∞, ∞) since exponential functions are defined for every x.
• Range: The basic function 2^x has a range of (0, ∞). After the vertical transformations, the range becomes (1, ∞) because the horizontal asymptote shifts to y = 1.
6. Key Points:
• Horizontal Asymptote: y = 1 (due to the +1 shift)
• x = 2 gives y = 4 · 2^(0) + 1 = 4 · 1 + 1 = 5. So, the point (2, 5) lies on the graph.
• For x = 0: y = 4 · 2^(0 – 2) + 1 = 4 · 2^(–2) + 1 = 4 · (1/4) + 1 = 1 + 1 = 2. Thus, the y-intercept is (0, 2).
Overall, the graph of y = 4 · 2^(x–2) + 1 is an exponentially increasing curve that has been shifted right 2 units and up 1 unit, and scaled vertically by a factor of 4.
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