Find the missing term in the proportion: $$ \frac{y}{16}=\frac{\frac{1}{6}}{\frac{1}{3}} $$ $$ y=\square $$

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To find the missing term $$ y $$ in the proportion $$ \frac{y}{16}=\frac{\frac{1}{6}}{\frac{1}{3}} $$, we can follow these steps:

1. **Calculate the right side of the equation**:
   We need to simplify $$ \frac{\frac{1}{6}}{\frac{1}{3}} $$.

This can be done by multiplying by the reciprocal of the denominator:
   $$
   \frac{\frac{1}{6}}{\frac{1}{3}} = \frac{1}{6} \times \frac{3}{1} = \frac{3}{6} = \frac{1}{2}
   $$

2. **Set up the equation**:
   Now we can rewrite the proportion:
   $$
   \frac{y}{16} = \frac{1}{2}
   $$

3. **Cross-multiply to solve for $$ y $$**:
   Cross-multiplying gives us:
   $$
   y \cdot 2 = 16 \cdot 1
   $$
   Simplifying this, we have:
   $$
   2y = 16
   $$

4. **Divide both sides by 2**:
   To isolate $$ y $$, we divide both sides by 2:
   $$
   y = \frac{16}{2} = 8
   $$

Thus, the missing term is $$ y = 8 $$.
$$ y = 8 $$

Find the missing term in the proportion: \( \frac{y}{16}=\frac{\frac{1}{6}}{\frac{1}{3}} \) \( y=\square \)

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